It appears to be a combustion reaction since the products are CO2 and
H2O . I don't think you can break it down or balance it as typed. I
think it needs an O2 reactant on the left side, as in the unbalanced
C12H22O11 + O2 = CO2 + H2O
From there, you have 12 C on the left and 1 on the right, so put a 12 in front of CO2 :
C12H22O11 + O2 = 12 CO2 + H2O
Now you have 22 H on the left and 2 H on the right, so put an 11 in front of H2O :
C12H22O11 + O2 = 12 CO2 + 11 H2O
Now you have 13 O on the left and 35 O on the right. To get to 35 O on the left, put a 12 in front of O2 :
C12H22O11 + 12 O2 = 12 CO2 + 11 H2O
and that's balanced.
?
· 3 years ago
