If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Molybdenum-99 follows first-order decay.
What is first-order decay?
First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.
The half-life (th) of Mo-99 is 66 h.
We will find its rate constant (k) using the following expression.
k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹
Next, we will convert 11 days to hours, knowing that 1 day = 24 h.
11 d × 24 h/1 d = 264 h
If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.
[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]
where,
- [Mo] is the final amount of Mo-99.
- [Mo]₀ is the initial amount of Mo-99.
- t is the elapsed time.
If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Learn more about first-order decay here: https://brainly.com/question/14478152
