ZJSG09112007
contestada

Using the following equation , solve the equation graphically for integral values of x any.
Plot a graph of the equations and shade out the area which is not in the range of values.

1.
[tex]y \geqslant 0 , \\ x - y \geqslant 1 , 3x + 4y < 12[/tex]
​

Respuesta :

mhanifa

Answer:

  • See the attached

Step-by-step explanation:

  • y ≥ 0 - limits the region to first and second quadrants
  • x - y ≥ 1 ⇒ y ≤ x - 1 (region A on the graph)
  • 3x + 4y < 12 ⇒ y < - 4/3x + 4 (region B on the graph)

Regions covered by each functions are shaded and the intersection also shaded and marked.

The white area in the graph is the out of range region.

Ver imagen mhanifa
sqdancefan

Answer:

  {(1, 0), (2, 0), (2, 1)}

Step-by-step explanation:

In the attached graph, the dashed lines are to be considered part of the unshaded area, hence in the solution set. The only points with integer coordinates in the solution set are the ones listed above.

Ver imagen sqdancefan

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