Sherbrooke, Quebec is 210 miles from Boston, MA. A train leaves Boston at noon and arrives in Sherbrooke at 4:40 PM. On the return trip to Boston, the train travels 50.4 mph. How many times greater (or less) is the train’s speed on the return trip to Boston than on the trip to Sherbrooke?

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sqdancefan sqdancefan · Answer 1 · 2021-02-15T00:01:22+01:00

9514 1404 393

Answer:

1.12 times as great

Step-by-step explanation:

The speed from Boston is ...

(210 mi)/(4 2/3 h) = 45 mi/h

Then the speed to Boston is ...

50.4/45 = 1.12 . . . times as great

__

The speed on the return trip is 1.12 times as great, or 12% greater than on the trip to Sherbrooke.

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maxplanchon2w maxplanchon2w · Answer 2 · 2021-02-21T17:32:04+01:00

9514 1404 393

Answer:

1.12 times as great

Step-by-step explanation:

The speed from Boston is ...

(210 mi)/(4 2/3 h) = 45 mi/h

Then the speed to Boston is ...

50.4/45 = 1.12 . . . times as great

__

The speed on the return trip is 1.12 times as great, or 12% greater than on the trip to Sherbrooke.

Answer Link