The number of sides in this polygon is 10.
For any polygon, the sum of interior angles is given as,
[tex]\bold{Sum\ of\ interior\ angles= {(n-2)}\times {180^o}}[/tex]
where,
n = number of sides,
We know that for a pentagon, the number of sides is 5.
thus, substituting the values in the sum of interior angle formula we get,
[tex]{Sum\ of\ interior\ angles= {(n-2)}\times {180^o}}[/tex]
[tex]{Sum\ of\ interior\ angles= {5-2}\times{180^o}}\\= 3 \times {180^o} = 540^o[/tex]
therfore, each angle in a regular pentagon,
[tex]\dfrac{Sum\ of\ interior\ angles}{Number\ of\ Sides} = \dfrac{540^o}{5} = 108^o[/tex],
Let's assume that polygon A is having x number of sides.
At point P, the sum of the angles must be 360°.
The sum of the angles at point P
= interior angle of the first pentagon
+ interior angle of the second pentagon
+ interior angle of the polygon A with x sides
Substituting the values,
360° = 108° + 108° + z
z = 360° - 108° - 108°
z = 144°
Thus, the interior angle of the x sided polygon is z = 144°.
For a regular polygon, all the interior angles are equal,
so, for a polygon with sides x.
the sum of interior angle = measure of interior angle x Number of sides
= [tex]144^o \times x[/tex]
Also, we know
[tex]{Sum\ of\ interior\ angles= {(n-2)}\times {180^o}}[/tex]
Substituting, the values for an x number of side polygon,
[tex]{Sum\ of\ interior\ angles= {(n-2)}\times {180^o}}\\{144^o \times x = {(x-2)}\times {180^o}}\\144x = 180x - 360\\360 = 180x- 144x\\x = \dfrac{360}{36}\\x = 10[/tex]
Hence, the number of sides in this polygon is 10.
To know more visit:
https://brainly.com/question/12749326
