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A theater group made appearances in two cities. The hotel charge before tax in the second city was $1500 higher than in the first. The tax in the first city was 4% , and the tax in the second city was 3.5% . The total hotel tax paid for the two cities was $408.75. How much was the hotel charge in each city before tax?

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Supernova11

Sorry for the delay!

Let x = charge before tax in 1st city, and y = charge before tax in 2nd city

y = $1500 + x

4/100x => tax in first city

3.5/100y => tax in second city

0.04x + 0.035y = $408.75

We have the following system of equations to solve:

[tex]\begin{bmatrix}y=1500+x\\ 0.04x+0.035y=408.75\end{bmatrix}\\\\\mathrm{Substitute\:}y=1500+x\\\\begin{bmatrix}0.04x+0.035\left(1500+x\right)=408.75\end{bmatrix}\\\begin{bmatrix}0.075x+52.5=408.75\end{bmatrix}\\\\\ x = 4750\\\mathrm{For\:}y=1500+x\\\mathrm{Substitute\:}x=4750:\\\\y=1500+4750 = 6250[/tex]

So the hotel charge before tax in city 1 = $4750, and the hotel charge before tax in city 2 = $6250

mhanifa

Answer:

  • $4750 and $6250

Step-by-step explanation:

Given

  • Hotel charge in city 1 = x
  • Hotel charge in city 2 = y

The equation for the hotel charge:

  • y = x + 1500

Taxes

  • Tax in the city 1 = 4% = 0.04x
  • Tax in the city 2 = 3.5% = 0.035y
  • Total tax = $408.75

The equation for the tax:

  • 0.04x + 0.035y = 408.75

Substitute y and solve for x:

  • 0.04x + 0.035(x + 1500) = 408.75
  • 0.04x + 0.035x + 52.5 = 408.75
  • 0.075x = 408.75 - 52.5
  • 0.075x = 356.25
  • x = 356.25/0.075
  • x = 4750

Find the value of y:

  • y = 4750 + 1500
  • y = 6250

The hotel charge was:

  • The first city: $4750
  • The second city: $6250

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