10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it
is bent in the form of a square, find the side of the square.

Respuesta :

Answer:

[tex]r = 42[/tex] --- radius

[tex]L = 66[/tex] -- Length of the square

Step-by-step explanation:

Given

[tex]Length = 264cm[/tex]

Solving (a): Find the radius (when it formed a circle).

The length of the wire represents the circumference (C) of the wire.

So, we have:

[tex]C = 2\pi r[/tex]

Make r the subject

[tex]r = \frac{C}{2\pi}[/tex]

Substitute 264 for C

[tex]r = \frac{264}{2\pi}[/tex]

[tex]r = \frac{132}{\pi}[/tex]

Take [tex]\pi[/tex] as 22/7

[tex]r = \frac{132}{22/7}[/tex]

[tex]r = \frac{132*7}{22}[/tex]

[tex]r = \frac{924}{22}[/tex]

[tex]r = 42[/tex]

Solving (b): Find the side length (when it formed a square).

The length of the wire represents the perimeter (P) of the wire.

So, we have:

[tex]P = 4L[/tex]

Make L the subject

[tex]L = \frac{1}{4}P[/tex]

Substitute 264 for P

[tex]L = \frac{1}{4}*264[/tex]

[tex]L = 66[/tex]

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