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Chloroform and ethyl alcohol have a denisty of 1.49 g/mL and 0.789 g/mL respectively. What volume of chloroform is required to match the amount of mass in 150 mL of ethyl alcohol?

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dsdrajlin

Answer:

79.2 mL

Explanation:

Step 1: Given data

  • Density of chloroform (ρC): 1.49 g/mL
  • Density of ethyl alcohol (ρE): 0.789 g/mL
  • Volume of ethyl alcohol (VE): 150 mL

Step 2: Calculate the mass corresponding to 150 mL of ethyl alcohol

We will use the definition of density.

ρE = mE/VE

mE = ρE × VE

mE = 0.789 g/mL × 150 mL = 118 g

We want the mass of chloroform to match the mass of ethyl alcohol. Then, mC = mE = 118 g

Step 3: Calculate the volume corresponding to 118 g of chloroform

We will use the definition of density.

ρC = mC/VC

VC = mC/ρC

VC = 118 g/ (1.49 g/mL) = 79.2 mL

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