Respuesta :

mhanifa

Answer:

  • 34

Step-by-step explanation:

Given

  • z = -3 + 5i

Conjugate of z is:

  • z' = -3 - 5i

Product zz' is:

  • zz' = (-3 + 5i)(-3 - 5i) = (-3)² - (5i)² = 9 - 25(-1) = 9 + 25 = 34

If ,

[tex]\bold{z=-3+5i }[/tex]

so,conjugate of z

[tex]\overline{ z }[/tex]=[tex]\bold{-3-5i }[/tex]

Because, in argand plane [tex]\overline{ z }[/tex] is the reflection of z in x-axis.

so,

According to the question,

z[tex]\overline{z}[/tex]=(-3+5i)(-3-5i)

[tex]\bold{(-3)^2-(5i)^2 }[/tex]

[tex]\bold{9-25(-1) }[/tex]

[tex]\bold{ 9+25 }[/tex]

[tex]\bold{ 34 }[/tex]

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