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1.Ms. Bowery bought five shirts and one pair of pants for a total of $56.23. Each shirt cost
the same price. The pants cost $7 more than a shirt. How much did each shirt cost? Round to
the nearest dollar and cent
A) $9.20
B) $49.26
C) $8.20
D) $10.20

Respuesta :

Answer:

[tex]\mathrm{C)\:} \$8.20[/tex]

Step-by-step explanation:

Let [tex]s[/tex] represent the cost of each shirt in dollars. We can write the cost of the pants as [tex]s+7[/tex]. Using these terms, set up the following equation:

[tex]5s+(s+7)=56.23[/tex].

Solving, we get:

[tex]5s+s+7=56.23,\\6s=56.23,\\6s=49.23\\s\approx \fbox{$\$8.20$}[/tex]
I believe it’s C. Because $8.20x5 is 41, then 8.50+7= $15.50 so then add 41+15.50= 56.50. That’s just my guess.

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