Respuesta :
Answer:
[tex]\displaystyle \frac{7x^2 + 4x - 20}{5x + 10} = \frac{7x - 10}{5}, x \neq -2[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Algebra I
- Terms/Coefficients
- Factoring
Calculus
Discontinuities
- Removable (Holes)
- Jump (Piece-wise functions)
- Infinite (Asymptotes)
Step-by-step explanation:
Step 1: Define
[tex]\displaystyle \frac{7x^2 + 4x - 20}{5x + 10}[/tex]
Step 2: Simplify
- [Frac - Numerator] Factor quadratic: [tex]\displaystyle \frac{(7x - 10)(x + 2)}{5x + 10}[/tex]
- [Frac - Denominator] Factor GCF: [tex]\displaystyle \frac{(7x - 10)(x + 2)}{5(x + 2)}[/tex]
- [Frac] Divide/Simplify: [tex]\displaystyle \frac{(7x - 10)}{5}, x \neq -2[/tex]
When we divide (x + 2), we would have a removable discontinuity. If we were to graph the original function, we would see at x = -2 there would be a hole in the graph.
[tex]\color{skyblue}{\boxed{\tt{ANSWER:}}}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
- Algebra I
Terms/Coefficients
Factoring
Calculus
Discontinuities
- Removable (Holes)
- Jump (Piece-wise functions)
- Infinite (Asymptotes)
^_^ ❤