Special Right Triangles

Answer:
first option
Step-by-step explanation:
Using the sine/ cosine ratios in the right triangle and the exact values
sin30° = [tex]\frac{1}{2}[/tex] , cos30° = [tex]\frac{\sqrt{3} }{2}[/tex]
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{32}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2x = 32 ( divide both sides by 2 )
x = 16
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cos30° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{y}{32}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2y = 32[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
y = 16[tex]\sqrt{3}[/tex]