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Collision practice

Running at 2.0 m/s, Bruce, the 45.0-kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision,
Biff wraps up Biff for the tackle. What is the resultant velocity of the players.

V=————— m/s

Collision practice Running at 20 ms Bruce the 450kg quarterback collides with Biff the 900 kg tackle who is traveling at 70 ms in the other direction Upon colli class=

Respuesta :

Answer:

[tex]v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}[/tex]

Explanation:

Using the Law of Conservation of Momentum, we can set up the following equation:

[tex]m_2v_2-m_1v_1=m_fv_f[/tex], where [tex]m_1v_1[/tex] is Bruce's momentum and [tex]m_2v_2[/tex].

Plugging in given values, we get:

[tex]90\cdot7-45\cdot2=(90+45)v_f, \\v_f=\frac{540}{135}=\fbox{$4\:\mathrm{m/s}$}[/tex].

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