Answer:
Silver
Explanation:
Given parameters:
Mass = 116g
Energy = 511J
Initial temperature = 21.6°C
Final temperature = 40.5°C
Unknown:
Specific heat capacity and the type of metal = ?
Solution:
To solve this problem, we need to find the specific heat capacity of the metal given,
H = m x c x Ф
H is the energy
m is the mass
c is the specific heat capacity
Ф is the change in temperature
511 = 116 x c x (40.5 - 21.6)
511 = 2192.4c
c = 0.233J/g°C
The specific heat capacity of silver is similar to this.
Answer:
READ THE EXPLAINATION
Explanation:
It says show your work.
40.5°C – 21.6°C = 18.9°C
So, the metal was raised 18.9 deg Celsius.
It took 511 J of energy to raise the metal 18.9 deg Celsius.
511/ 18.9 = 27.03
It takes 27.03 J to raise 116 g of the metal 1 degree.
27.03/116 = .233
It takes .233 J to raise 1 gram of the metal 1 degree.
Therefore, the specific heat capacity of the metal is .233 J
According to the Specific heat values table, Silver has a specific heat capacity of .233.
The metal is silver.
