Answer:
[tex]h_m=5 \ m[/tex]
Explanation:
Projectile Motion
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.
The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:
[tex]\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}[/tex]
Where:
vo = initial speed of the object
θ = initial launch angle
g = acceleration of gravity ([tex]10\ m/s^2[/tex])
The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:
[tex]\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}[/tex]
[tex]\displaystyle h_m=\frac{400\cdot 0.5^2}{20}[/tex]
[tex]\boxed{h_m=5 \ m}[/tex]
