Which function is the inverse of g(x) = [tex]\frac{(x-1)^{3} }{2} -3[/tex]?

Answer:
third option
Step-by-step explanation:
let g(x)=y
(x-1)³/2-3=y
(x-1)³/2-3/1=y
(x-1)³-6/2=y
(x-1)³-6=2y
(x-1)³=2y+6(find cubic root of both sides)
(x-1)=³√(2y+6)
x=³√(2y+6)+1
Replace y with g for the inverse
g^-1(x)=³√(2x+6)+1