Answer:
Given that you're providing only a single term, asking for a difference doesn't make a lot of sense. I assume you're asking to have the expression simplified?
If so, then it can be reduced to (x - 17) / 3x
Step-by-step explanation:
You can simplify by multiplying both terms each by a different ratio that equals one, but also gives the terms common denominator. Multiplying the first one by x²/x² and the second by 3x/3x will do that for you.
After that you can group the terms into one fraction and simplify:
[tex]\frac{x - 8}{3x} - \frac{3x}{x^2} \\\\= \frac{x - 8}{3x}\times\frac{x^2}{x^2} - \frac{3x}{x^2} \times\frac{3x}{3x} \\\\= \frac{x^3 - 8x^2}{3x^3} - \frac{9x^2}{3x^3} \\\\= \frac{x^3 - 8x^2 - 9x^2}{3x^3} \\\\= \frac{x - 8 - 9}{3x}\\\\= \frac{x - 17}{3x}\\[/tex]
Answer:
The difference of [tex]\frac{x-8}{3x}-\frac{3x}{x^2}[/tex] is [tex]\mathbf{\frac{x-17}{3x}}[/tex]
Step-by-step explanation:
We need to find the difference: [tex]\frac{x-8}{3x}-\frac{3x}{x^2}[/tex]
Simplifying to find the difference:
[tex]\frac{x-8}{3x}-\frac{3x}{x^2}[/tex]
x is common in both 3x and x^2 so, we can cancel it out and we get:
[tex]=\frac{x-8}{3x}-\frac{3x}{x(x)}\\=\frac{x-8}{3x}-\frac{3}{x}[/tex]
Now, taking LCM of 3x and x we get 3x, We will multiply 3x with both terms and then solve we get:
[tex]=\frac{x-8-3(3)}{3x}\\=\frac{x-8-9}{3x}\\=\frac{x-17}{3x}[/tex]
It cannot be further simplified, so we get [tex]\frac{x-17}{3x}[/tex] as answer.
So, The difference of [tex]\frac{x-8}{3x}-\frac{3x}{x^2}[/tex] is [tex]\mathbf{\frac{x-17}{3x}}[/tex]
