Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of [tex]NaClO_3[/tex].
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles[/tex]
The balanced chemical equation for decomposition of [tex]NaClO_3[/tex] is:
[tex]2NaClO_3\rightarrow 2NaCl+3O_2[/tex]
According to stoichiometry :
2 moles of [tex]NaClO_3[/tex] give = 2 moles of [tex]NaCl[/tex]
Thus 0.113 moles of [tex]NaClO_3[/tex] give =[tex]\frac{2}{2}\times 0.113=0.113moles[/tex] of [tex]NaCl[/tex]
Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of [tex]NaClO_3[/tex].
