Answer:
[tex]x=-4,\:x=-\frac{1}{5}[/tex]
Step-by-step explanation:
The zeroes of the function [tex]g(x)=(-5x-1)(2x+8)[/tex] can be found by setting [tex]g(x)[/tex] to [tex]0[/tex], then solving for [tex]x[/tex]:
[tex](-5x-1)(2x+8)=0[/tex]
When either term is [tex]0[/tex], the equation is true. Therefore we have two cases:
[tex]\begin{cases}-5x-1=0,\: -5x=1, \:\fbox{$x=-\frac{1}{5}$}\\2x+8=0,\:2x=-8,\:\fbox{$x=-4$}\\\end{cases}[/tex]
Answer:
lesser is -4
greater is-1/5
Step-by-step explanation:
just did it on khan
