Answer:
Area of rectangle = [tex]\mathbf{x^2-4x}[/tex]
Perimeter of rectangle = [tex]\mathbf{4x-8}[/tex]
Step-by-step explanation:
We are given:
Length of rectangle = x
Width of rectangle = x-4
We are not given if we want to find area of rectangle or perimeter of rectangle.
So, I will be finding both
Area of rectangle
The formula used is: [tex]Area\: of\: rectangle=Length \times Width[/tex]
Putting values and finding area
[tex]Area\: of\: rectangle=Length \times Width\\Area\: of\: rectangle=x \times (x-4)\\Area\: of\: rectangle=x^2-4x[/tex]
So, we get area of rectangle = [tex]\mathbf{x^2-4x}[/tex]
Perimeter of rectangle
The formula used is: [tex]Perimeter \: of\: rectangle=2(Length+ Width)[/tex]
Putting values and finding perimeter
[tex]Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8[/tex]
So, we get perimeter of rectangle = [tex]\mathbf{4x-8}[/tex]
I hope, it can help in solving the question.
