contestada

1)
If I have 45 liters of helium in a balloon at 25°C and increase the
temperature of the balloon to 55° C, what will the new volume of the
balloon be?

Respuesta :

Answer:

52.8 Liters

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

  • P1 = 45
  • T1 (in Kelvins) = 25 + 273.1 =298.1
  • P2= ?
  • T2 = 55 + 273.1 = 328.1

then:

45/298.1 = P2/328.1

P2 = 52.8

The new volume of the balloon is 52.8 Liters this can be calculated by using gas laws.

Charles law:

Charles law states the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature. It is given by

V₁/T₁ = V₂/T₂

What information do we have?

V₁ = 45 L

T₁ = 25 + 273.1 =298.1 K

T₂ = 55 + 273.1 = 328.1 K

To find:

V₂= ?

On substituting the values:

45/298.1 = V₂/328.1

V₂ = 52.8 L

Thus, the volume of the balloon is 52.8 liters.

Find more information about Gas law here:

brainly.com/question/555495

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