If equal amounts of helium and argon are placed in a porous container and allowed to escape, helium will diffuse 3.16x faster than argon.
According to Graham's law of diffusion of gases, the rate of diffusion of a gas is inversely related to the square root of its molecular weight.
Mathematically, when two gases are being compared;
r1/r2 = √m2/√m1
Where r1 = diffusion rate of gas 1, r2 = difussion rate of gas 2, m1 = molar weight of gas 1, and m2 = molar weight of gas 2.
Molar weight of helium = 4
Molar weight of argon = 39.9
Hence,
r helium/r argon = √39.9/√4
= 6.317/2
= 3.16
Therefore, 3.16 x r argon = r helium.
In other words, helium will diffuse 3.16x faster than argon.
More on diffusion rate of gases can be found here: https://brainly.com/question/2967915
