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Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

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LILBREE0916

Answer:

Step-by-step explanation:

Only the term 2πrh contains h.  Isolate this term on the right by subtracting 2πr^2 from both sides:

S - 2πr^2 = 2πrh

Now divide the left side by 2πr, obtaining:

        s - 2πr^2

h =   ------------------

The equation S =  2πrh + 2πr² to solve for h is as follows:

h = S - 2πr² /  2πr

How to find the subject of formula in an equation

S =  2πrh + 2πr²

We want to make h the subject of the formula,

Therefore,

S = 2πrh + 2πr²

subtract 2πr² from both sides

S - 2πr² = 2πrh

divide both sides by  2πr

Therefore,

S - 2πr² /  2πr =  2πrh /  2πr

Hence,

h = S - 2πr² /  2πr

learn more on equation here: https://brainly.com/question/13858149

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