Answer:
[tex]\left(3x^2+5x-8\right)-\left(4x^2-x+6\right)=-x^2+6x-14[/tex]
Hence, option D is correct.
Step-by-step explanation:
We have to subtract (4x² - x + 6) from (3x² + 5x - 8).
so
[tex]\left(3x^2+5x-8\right)-\left(4x^2-x+6\right)[/tex]
Remove parentheses: [tex]\left(a\right)=a[/tex]
[tex]=3x^2+5x-8-\left(4x^2-x+6\right)[/tex]
[tex]=3x^2+5x-8-4x^2+x-6[/tex]
Group like terms
[tex]=3x^2-4x^2+5x+x-8-6[/tex]
Add similar elements: [tex]\:3x^2-4x^2=-x^2[/tex]
[tex]=-x^2+5x+x-8-6[/tex]
Add similar elements: [tex]5x+x=6x[/tex]
[tex]=-x^2+6x-8-6[/tex]
Subtract the numbers: [tex]-8-6=-14[/tex]
[tex]=-x^2+6x-14[/tex]
Therefore,
[tex]\left(3x^2+5x-8\right)-\left(4x^2-x+6\right)=-x^2+6x-14[/tex]
Hence, option D is correct.
