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In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a speed of 67 m/s, what is the force exerted by the racket on the ball

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pstnonsonjoku

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

asuwafohjames

The force exerted by the racket on the ball is 3015 N.

The force exerted by the racket on the ball is given in the formula below.

⇒ Formula:

  • F = mΔv/t............... Equation 1

⇒ Where:

  • F = force exerted by the racket
  • m = mass of the birdy
  • Δv = change in speed
  • t = time.

From the question,

⇒ Given:

  • m = 0.045 kg
  • Δv = 67 m/s
  • t = 0.0010 seconds.

⇒ Substitute these values into equation 1

  • F = 0.045(67)/0.001
  • F = 3015 N

Hence, The force exerted by the racket on the ball is 3015 N

Learn more about Force here: https://brainly.com/question/13370981

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