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The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), butanoic acid (C3H7COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive

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Answer:

MgBr2 > KBr > C3H7COOH > C6H12O6

Explanation:

A strong electrolyte is a solution that dissociate completely in solution. A weak electrolyte does not dissociate completely in solution. The more the number of particles in solution, the more the conductivity of the solution.

For the substances Lister in the question;

MgBr2(aq) ------> Mg^2+(aq) + 2Br^-(aq)

KBr(aq) -----> K^+(aq) + Cl^-(aq)

C3H7COOH(aq) ------->C3H7COO^-(aq) + H^+(aq) (poorly dissociates)

C6H12O6 does not dissociate because it is molecular

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