Answer:
[tex]v=10^4\ m/s[/tex]
Explanation:
Given that,
The length of a vacuum tube, d = 2 m
Time, [tex]t=2\times 10^{-4}\ s[/tex]
We need to find the average speed of the electron during this time. Average speed is equal to total distance covered divided by total time taken.
Here, total distance = length of the vacuum tube
[tex]v=\dfrac{2}{2\times 10^{-4}}\\\\=10^4\ m/s[/tex]
So, the average speed of the electron is [tex]10^4\ m/s[/tex].
