Answer: the percentage of women that are shorter than 68.5 inches is 84.1%
Step-by-step explanation:
Given that;
mean μ = 65
standard deviation σ = 3.5
percentage of women are shorter than 68.5 inches = ?
P( x < 68.5 ) = P(( x-μ)/σ)
we substitute
⇒ ( 68.5-65)/3.5)
⇒ P(z < 1)
form standard normal table
P( x < 68.5 ) = P(z < 1) = 0.84134 ≈ 84.1%
Therefore, the percentage of women that are shorter than 68.5 inches is 84.1%
