Answer:
1120 L.
Explanation:
Hello!
In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.
In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:
[tex]V_2=\frac{V_1*n_2}{n_1}[/tex]
Thereby, we plug in to obtain:
[tex]V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L[/tex]
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