Answer:
5.2 × 10²² particles NaCl
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
5.0 g NaCl
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Na - 22.99 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol
Step 3: Convert
[tex]5.0 \ g \ NaCl(\frac{1 \ mol \ NaCl}{58.44 \ g \ NaCl} )(\frac{6.022 \cdot 10^{23} \ particles \ NaCl}{1 \ mol \ NaCl} )[/tex] = 5.15229 × 10²² particles NaCl
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
5.15229 × 10²² particles NaCl ≈ 5.2 × 10²² particles NaCl
