Answer:
[tex]\approx 91^\circ[/tex]
Step-by-step explanation:
The given equation to represent the model for the relationship between [tex]x[/tex] and [tex]y[/tex].
[tex]y=6.88x-199[/tex]
[tex]x[/tex] represents the air temperature in degrees and
[tex]y[/tex] represents the number of visitors at a pool.
Also given that number of visitors at the pool on a particular day is 426.
To find:
The expected air temperature as per the number of visitors.
Solution:
Here, we are given a linear equation to represent the relation between two variables.
Value of one variable is given and we have to find the value of other variable.
i.e. we are given that:
[tex]y=426[/tex] and we have to find the value of [tex]x[/tex].
Let us put the value in the equation:
[tex]426=6.88x-199\\\Rightarrow 6.88x = 426 + 199\\\Rightarrow x = \dfrac{625}{6.88}\\\Rightarrow \bold{x \approx 91^\circ}[/tex]
