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The hare challenged the tortoise to a rematch race. This time, the hare ran the same speed of 15 meters per second the whole race. The hare didn't even take nap this time. To be nice, the hare gave the tortoise a head start. The tortoise started 200 meters ahead. The tortoise ran 7 meters per second. Create a system of equations to model this situation.​

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theleangreenbean

Answer:

[tex]\left \{ {{h=15s} \atop {t=7s+200}} \right.[/tex]

Step-by-step explanation:

Let [tex]h[/tex] be equal to the number of meters the hare travels.

Let [tex]t[/tex] be equal to the number of meters the tortoise travels.

Let [tex]s[/tex] be equal to the number of seconds that pass.

The hare travels at a speed of 15 meters per second, which means [tex]15s[/tex] represents the number of meters the hare travels depending on the number of seconds that pass.

[tex]h=15s[/tex]

The tortoise travels at a speed of 7 meters per second, which means [tex]7s[/tex] represents the number of meters the tortoise travels depending on the number of seconds that pass.

[tex]t=7s[/tex]

However, because the tortoise got a 200-meter head start, we need to add 200 meters to our equation.

[tex]t=7s+200[/tex]

Here is our system of equations:

[tex]\left \{ {{h=15s} \atop {t=7s+200}} \right.[/tex]

I hope this helps!

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