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A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, in units of m/s?

Respuesta :

bomdamini

Answer:

2700

Explanation:

because calculate the minute1=60×45=2700

mberisso

Answer:

[tex]v \approx 30.67\,\,\frac{m}{s}[/tex]

Explanation:

We use the kinematic formula for constantly accelerated motion given below:

[tex]v^2=v_0^2+2\,a\Delta x\\v^2=0+2\,g\,(48)\\v^2=940.8\\v \approx 30.67\,\,\frac{m}{s}[/tex]

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