Given that,
The cone and the sphere have the same volume.
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Volume of the cone
[tex] = \frac{1}{3}\pi {r}^{2} h[/tex]
[tex] = \frac{1}{3} \times \frac{22}{7} \times 2.4 \times 2.4 \times 8.3[/tex]
[tex] = 1 \times \frac{22}{7} \times 0.8 \times 2.4 \times 8.3[/tex]
[tex] = \frac{22}{7} \times 1.92 \times 8.3[/tex]
[tex] = \frac{22}{7} \times 15.93[/tex]
[tex] = 22 \times 2.27[/tex]
[tex] = 49.94[/tex]
[tex] = 50 {cm}^{3} (rounded)[/tex]
Also,
Volume of the sphere
= 50cm³
[tex] = \frac{4}{3} \pi {r}^{2} = 50[/tex]
[tex] \pi {r}^{2} = 50 \times \frac{3}{4} [/tex]
[tex]\pi {r}^{2} = 37.5[/tex]
