Answer:
[tex]2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}[/tex]
Step-by-step explanation:
Given the expression
[tex]2ab^2-\frac{a^2b^2}{5}[/tex]
[tex]\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}[/tex]
[tex]2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}[/tex]
[tex]\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}[/tex]
[tex]=\frac{2ab^2\cdot \:5-a^2b^2}{5}[/tex]
[tex]=\frac{10ab^2-a^2b^2}{5}[/tex]
Thus,
[tex]2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}[/tex]
