Answer:
[tex]\boxed {\boxed {\sf 53, 346 \ Joules}}[/tex]
Explanation:
We are given the specific heat and change in temperature, so we should use this heat formula:
[tex]q=m C \Delta T[/tex]
where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.
Let's find the change in temperature.
Subtract the initial temperature from the final temperature.
Now we know all the values:
[tex]m= 150 \ g \\C= 4.184 J/ g \ \textdegree C \\\Delta T= 85.0 \textdegree C[/tex]
Substitute them into the formula.
[tex]q=(150 \ g) (4.184 \ J/g \ \textdegree C)(85.0 \textdegree C )[/tex]
Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.
[tex]q=(627.6 \ J/ \textdegree C) ( 85.0 \textdegree C)[/tex]
[tex]q=53346 \ J[/tex]
53,346 Joules of heat are required.
