Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Answer:
(a). y = 3x - 11 ; (b). y = [tex]-\frac{1}{3}[/tex] x - 1
Step-by-step explanation:
Parallel lines have the same slopes
Slopes of perpendicular lines are opposite reciprocals.
(3, - 2)
The slope of given line is 3
(a). Equation of ║ line is
y + 2 = 3(x - 3)
y = 3x - 11
(b). Slope of perpendicular line is [tex]-\frac{1}{3}[/tex]
y + 2 = [tex]-\frac{1}{3}[/tex] (x - 3)
y = [tex]-\frac{1}{3}[/tex] x - 1
The required equation of a line parallel to the line will be y = 3x - 7
The required equation of the perpendicular line is y = -1/3 - 7
Using the coordinate points to get the equation of the line (1, -4) and (2, -1)
The standard form of the equation is expressed as y = mx + b
m is the slope
b is the y-intercept
Get the slope:
m = y2-y1/x2-x1
m = -1+4/2-1
m = 3/1
m = 3
Get the y-intercept
-4 = 3(1) + b
b = -4-3
b = -7
The required equation of a line parallel to the line will be y = 3x - 7
For the equation of the line perpendicular, the slope of the line will be -1/3
The required equation of the perpendicular line is y = -1/3 - 7
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