Answer:
[tex]x-2y=-6[/tex]
Step-by-step explanation:
The line contains a slope of 1/2 and has a y-intercept of 3.
And we want to write this in standard form.
Let’s first write it in slope-intercept form:
[tex]y=mx+b[/tex]
Where m is the slope and b is the y-intercept.
So, substitute 1/2 for m and 3 for b. This yields:
[tex]y=\frac{1}{2}x+3[/tex]
We will convert this to standard form. The standard form is:
[tex]Ax+By=C[/tex]
Where A, B, and C are all integers, and A is positive.
We have the slope-intercept equation:
[tex]y=\frac{1}{2}x+3[/tex]
So, let’s multiply our slope-intercept equation by 2 to remove the fraction. This gives us:
[tex]2y=x+6[/tex]
Now, subtract x from both sides:
[tex]-x+2y=6[/tex]
The coefficient of x should be positive. So, multiply both sides by -1:
[tex]x-2y=-6[/tex]
Hence, our standard form is:
[tex]x-2y=-6[/tex]
