Length of the rectangle (l) = x + 5
Perimeter of the rectangle = 4x + 14
Formula of perimeter of the rectangle = 2(length + width)
Let the width of the rectangle be 'w'. So,
[tex] \rm \longrightarrow 2(l + w) = 4x + 14 \\ \\ \rm \longrightarrow 2(x + 5 + w) = 4x + 14 \\ \\ \rm \longrightarrow \dfrac{2(x + 5 + w)}{2} = \dfrac{4x + 14}{2} \\ \\ \rm \longrightarrow x + 5 + w = 2x + 7 \\ \\ \rm \longrightarrow x + 5 + w - (x + 5) = 2x + 7 - (x + 5) \\ \\ \rm \longrightarrow x - x + 5 - 5 + w = 2x - x + 7 - 5 \\ \\ \rm \longrightarrow w = x + 2[/tex]
[tex] \therefore [/tex] Width of the rectangle (w) = x + 2
