Answer:
The length of segment QA when Q(-7,10) and A(3,4) is √136 or 11.66 units
Step-by-step explanation:
Given points are:
Q(-7,10) and A(3,4)
Here
[tex](x_1,y_1) = (-7,10)\\(x_2,y_2) =(3,4)[/tex]
The distance between two points is the length of the segment formed by those two points. The distance between 2 points is given by:
[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Putting the values
[tex]d = \sqrt{(3-(-7))^2+(4-10)^2}\\d = \sqrt{(3+7)^2+(-6)^2}\\d = \sqrt{(10)^2+(-6)^2}\\d = \sqrt{100+36}\\d = \sqrt{136}\\d= 11.66\ units[/tex]
Hence,
The length of segment QA when Q(-7,10) and A(3,4) is √136 or 11.66 units
