Answer:
[tex][f(x)]^2-g(x) = 5x^2-13x-8[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 2x-2\\g(x) = -x^2+5x+12[/tex]
To find: [tex][f(x)]^2-g(x)[/tex]
First of all the square of first function f(x) will be found and then second function g(x) will be subtracted from the square of first function
Squaring the first function
[tex][f(x)]^2 = (2x-2)^2\\Using\ (a-b)^2 = a^2-2ab+b^2\\\[f(x)]^2 = (2x)^2-2(2x)(2)+(2)^2\\= 4x^2-8x+4[/tex]
Now subtracting g(x) from [f(x)]^2
[tex][f(x)]^2-g(x) = (4x^2-8x+4)-(-x^2+5x+12)\\\[f(x)]^2-g(x) = 4x^2-8x+4+x^2-5x-12[/tex]
Combining alike terms
[tex][f(x)]^2-g(x) = 4x^2+x^2-5x-8x+4-12\\\[f(x)]^2-g(x) = 5x^2-13x-8[/tex]
Hence,
Subtracting g(x) from the square of f(x) gives us:
[tex][f(x)]^2-g(x) = 5x^2-13x-8[/tex]
