If sin t = -8/17 and t is a quadrant III angle, find cot t

Answer:cot t = 1.875
[tex]sin t=\frac{-8}{17}[/tex] but sin²t + cos²t = 1 ⇔ cos²t = 1 - sin²t
⇔cos t = [tex]\sqrt{1-sin^{2}t }=\sqrt{1-(\frac{-8}{17})^{2} }=|\frac{15}{17}|[/tex]
but t is a quadrant III angle => cos t = [tex]\frac{-15}{17}[/tex]
=> cot t = [tex]\frac{-15}{17}:\frac{-8}{17}=\frac{15}{8}=1.875[/tex]
Step-by-step explanation: