Answer:
4 + 2√3
Step-by-step explanation:
x - 2 = √4x
Domain: √4x ≥ 0 ⇒ x - 2 ≥ 0 ⇒ x ≥ 2
(x - 2)² = (√4x)²
x² - 4x + 4 = 4x
x² - 8x + 4 = 0
D = (- 8)² - 4(1)(4) = 48 = (4√3)²
[tex]x_{1}[/tex] = [tex]\frac{8+4\sqrt{3} }{2}[/tex] = 4 + 2√3 ≈ 7.4641
[tex]x_{2}[/tex] = [tex]\frac{8-4\sqrt{3} }{2}[/tex] = 4 - 2√3 ≈ 0.5359 < 2 ⇒ [tex]x_{2}[/tex] is extraneous root
