In your Punnett Square activity, you chose beads which represented
genes and used Punnett Squares to determine possible offspring. If
your first parent genotype was yellow bead and blue bead and the
second parent genotype was blue bead and blue bead, how many
offspring out of 4 have the yellow kernel phenotype?
please please!!

The information that we have is that one parent's genotype is yellow bead (Y) and blue bead (B), and the other parent's genotype is blue bead (B) and blue bead (B).

Parent 1: YB

parent2: BB

If we make a Punnett Square, we can see that two out of four offspring will have the yellow phenotype.

║ B ║ B ║

Y║ YB ║ YB ║

B ║ BB ║ BB ║

Histrionicus Histrionicus · Answer 2 · 2021-11-18T11:31:53+01:00

The offspring out of 4 have the yellow kernel phenotype in the given case would be - two or 50%

We are given that the kernel color is represented by two beads, yellow and blue beads.

Let us consider yellow bead be represented as Y and blue bead be represented as y. Yellow color is dominant over blue kernel color.

parent 1 has a genotype of a yellow bead and a blue bead represented as Yy.

parent 2 has a genotype of the blue bead and blue bead, i.e, yy.

The cross can be given as,

Genotype Y y

y Yy yy

Now, two of the four offspring have Yy genotypes.

Thus, 2/4 or 50% of the offspring have a yellow kernel phenotype.

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