Answer:
The table is 2.08 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If we know the range d = 0.15 m and the speed v = 0.23 m/s, we can solve the above equation for h:
[tex]\displaystyle h=\frac{d^2\cdot g}{2v^2}[/tex]
[tex]\displaystyle h=\frac{0.15^2\cdot 9.8}{2\cdot 0.23^2}[/tex]
[tex]\boxed{h=2.08\ m}[/tex]
The table is 2.08 m high