Respuesta :
Answer:
2y + ( x- 20)= 500
y= 520-x/2
Step-by-step explanation:
Let the weight of George be x and the weight of the suspect be y .
The swing can hold a maximum of 500 pounds .
Twice the weight of suspect added with 20 pounds less than the weight of George equals 500.
2y + ( x- 20)= 500
or
2y+x- 20 = 500
adding 20 to both sides
2y+x -20 +20= 500+ 20
or
2y +x = 520
Subtracting x from both sides
2y+ x-x = 520-x
or
2y = 520-x
Dividing by 2 on both sides
y= 520-x/2
The suspect's weight is y= 520-x/2
Answer:
s = 260 - g/2
Step-by-step explanation:
Given the following :
Maximum weight swing can hold = 500 pounds
Let suspect's weight = s
George's weight = g
To reach maximum weight :
Double weight of suspect + (George's weight - 20)
Hence, equation:
2s + (g - 20) = 500
2s + g - 20 = 500
2s + g = 500 + 20
2s + g = 520
2s = 520 - g
Divide through by 2
s = 260 - g/2