Answer: 0.2877
Step-by-step explanation:
Given : The proportion of eggs will be damaged in route to the stores = 15% = 0.15
Sample size = 100
Let p be the probability of her eggs will be damaged.
The probability that less than 13% will be damaged is given by :-
[tex]P(p<0.13)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}<\dfrac{0.13-0.15}{\sqrt{\dfrac{0.15\times(1-0.15)}{100}}})[/tex]
[tex]=P(z<-0.56)[/tex]
[tex]=1-P(z<0.56)\\\\= 1-0.7123\\\\= 0.2877[/tex]
Hence, the required probability = 0.2877
