We want to find the roots of a quadratic equation, to do that, we will use the Bhaskara's formula.
For an equation like a*x^2 + b*x + c = 0
The solutions are given by:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]
Using that formula we will get that the solutions in ascending order are -1 and 5.
Now let's see how to get that:
We have expression: x^2 - 4x = 5
We can rewrite this as:
x^2 - 4x - 5 = 0
Now we can use the Bhaskara's formula to get:
[tex]x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*(-5)} }{2*1} = \frac{4 \pm6}{2*1}[/tex]
Then the two solutions are:
x = (4 + 6)/2 = 5
x = (4 - 6)/2 = -1
Then the solutions in ascending order are -1 and 5.
If you want to learn more, you can read:
https://brainly.com/question/23033812
