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A baseball is thrown vertically downward from the top of a 155 m tower with an initial velocity of -25 m/s. How long will it take, until it reaches the ground?

Respuesta :

Answer:

t = 2.55 s

Explanation:

Given that,

Height from which the baseball is thrown, h = 155 m

Initial velocity of the baseball, u = -25 m/s

We need to find the time taken by it to reach the ground. Let the time is t. Using equation of kinematics to find it as follows:

[tex]v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{0-(-25)}{9.8}\\\\t=2.55\ s[/tex]

So, it will take 2.55 seconds to reach the ground.

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