contestada

A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the acceleration

A marble accelerates from rest at a constant rate it travels 36 m in 120 sec whats is its final velocity and what was the acceleration class=

Respuesta :

dsdrajlin

Answer:

a = 0.50 m/s²

v = 6.0 m/s

Explanation:

Step 1: Given data

  • Initial velocity (u): 0 m/s (rest)
  • Displacement of the marble (s): 36 m
  • Time elapsed (t): 12.0 s
  • Final velocity (v): ?
  • Acceleration (a): ?

Step 2: Calculate the acceleration

We will use the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 × 12.0 s + 1/2 × a × (12.0 s)²

36 m = a × 72.0 s²

a = 0.50 m/s²

Step 3: Calculate the final velocity

We will use the following suvat equation.

v = u + a × t

v = 0 + 0.50 m/s² × 12.0 s

v = 6.0 m/s

Otras preguntas